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Math Help - indefinate area check.

  1. #1
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    indefinate area check.

    find area under graph y = \frac{1}{x^2} between x=1/3 and x=1/2

     <br />
\int_{1/3}^{1/2} \frac {x^-1}{-1}<br />
    this correct?
    then i substitute the intervals?
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  2. #2
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    Quote Originally Posted by jvignacio View Post
    find area under graph y = \frac{1}{x^2} between x=1/3 and x=1/2

     <br />
\int_{1/3}^{1/2} \frac {x^-1}{-1}<br />
    this correct?
    then i substitute the intervals?
    There should be no integral sign after you've done the integration. It should be \left[ \frac{x^{-1}}{-1}\right]_{1/3}^{1/2}, which can be re-written in simpler form as \left[ - \frac{1}{x}\right]_{1/3}^{1/2}. Then you substitute the integral terminals in the usual way.
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