Use the trigonometric identity $\displaystyle cos2x=1-2sin^2x$ to figure out $\displaystyle \int sin^2x dx$ having problems with this one. thank you
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Originally Posted by jvignacio Use the trigonometric identity $\displaystyle cos2x=1-2sin^2x$ to figure out $\displaystyle \int sin^2x dx$ having problems with this one. thank you $\displaystyle \int \sin^2{x}dx = \int \frac{1 - \cos{2x}}{2}dx$ The second integral easier to do
Originally Posted by 11rdc11 $\displaystyle \int \sin^2{x}dx = \int \frac{1 - \cos{2x}}{2}dx$ The second integral easier to do thank you ill give it a try
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