This is what I found

The p-series is given by

Σ[1/(n^p)] = 1/(1^p) + 1/(2^p) + 1/(3^p) + ...

where p > 0 by definition.

If p > 1, then the series converges.

If 0 < p <= 1 then the series diverges.

Since 3/2 > 1, the series should converge. Hope this helps.