Trying to find the antiderivative of (3x-1)^4 dx I know the answer but can't figure out how to work the problem to get it.
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Originally Posted by McDiesel Trying to find the antiderivative of (3x-1)^4 dx I know the answer but can't figure out how to work the problem to get it. $\displaystyle \int(3x-1)^4dz\overbrace{\mapsto}^{3x-1=z}\frac{1}{3}\int{z^4}dz$
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