i cant seem to figure this out
find the integral of
log(base 8) (2x+1) dx
i'm not sure how to approach this problem
i assume theres some integration by parts
so would it be like this
intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)
please help
i cant seem to figure this out
find the integral of
log(base 8) (2x+1) dx
i'm not sure how to approach this problem
i assume theres some integration by parts
so would it be like this
intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)
please help