i cant seem to figure this out

find the integral of

log(base 8) (2x+1) dx

i'm not sure how to approach this problem

i assume theres some integration by parts

so would it be like this

intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)

please help

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- Nov 10th 2008, 12:27 PMLone21integration help
i cant seem to figure this out

find the integral of

log(base 8) (2x+1) dx

i'm not sure how to approach this problem

i assume theres some integration by parts

so would it be like this

intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)

please help - Nov 10th 2008, 12:38 PMMathstud28