# integration help

• Nov 10th 2008, 12:27 PM
Lone21
integration help
i cant seem to figure this out
find the integral of
log(base 8) (2x+1) dx

i'm not sure how to approach this problem
i assume theres some integration by parts
so would it be like this
intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)
• Nov 10th 2008, 12:38 PM
Mathstud28
Quote:

Originally Posted by Lone21
i cant seem to figure this out
find the integral of
log(base 8) (2x+1) dx

i'm not sure how to approach this problem
i assume theres some integration by parts
so would it be like this
intg( LOG(b8) (2x+1)dx=(x^2+x)(LOGb8) - intg(x^2+x/8)
\begin{aligned}\int\log_8(2x+1)dx&=\frac{1}{\ln(8) }\int\ln(2x+1)dx\\