differentiate the following function with respect to x ln(3x-1) thanks
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Recall that: $\displaystyle \frac{d}{dx} \ln{x} = \frac{1}{x}$ $\displaystyle \frac{d}{dx}\ln{(3x-1)} = \frac{1}{3x-1} \cdot 3 = \frac{3}{3x-1}$
ahhh yes i remember now thanks, what about sin5x ?
actually, on the previous reply, why do you times it by 3?
$\displaystyle \frac{d}{dx}\sin{x} = \cos{x}$ $\displaystyle \frac{d}{dx}\sin{5x} = 5\cos{5x}$
Originally Posted by djmccabie actually, on the previous reply, why do you times it by 3? Because you have to apply the chain rule.
thanks dude, ask some silly questions when i type before i think =]
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