hi guys, i need help finding the anti-derivatives for these problems

Any help woud be appreciated

y' = tan(x)sec^2(x)

y' = 3x^(-1/2)

y' = -2cot^2(x)csc(x)

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- Nov 9th 2008, 04:53 PMsessanti-derivative problems
hi guys, i need help finding the anti-derivatives for these problems

Any help woud be appreciated

y' = tan(x)sec^2(x)

y' = 3x^(-1/2)

y' = -2cot^2(x)csc(x) - Nov 9th 2008, 05:00 PMChris L T521
- Nov 9th 2008, 05:06 PMsess
aight these are the answers that i got

y' = tan(x)sec^2(x) -> y = sec^2(x)tan(x)

y' = 3x^(-1/2) -> y = 1/(2x^(3/2))

y' = -2cot^2(x)csc(x) -> y = 2 (ln(abs(sin(x))))(csc(x))

did i get it? - Nov 9th 2008, 05:16 PMsess
pls help me out guys

- Nov 9th 2008, 05:18 PM11rdc11
Take the derivative of your answer and if it matches your integral than it is right.

The answer for the 1st is

$\displaystyle \frac{\sec^2{x}}{2} + c$ - Nov 9th 2008, 05:29 PMsess
can u show me the steps on how u got that answer please?

- Nov 9th 2008, 05:35 PM11rdc11
- Nov 9th 2008, 05:42 PMsess
ok Ive no idea wat u just said

i do know that the first derivative of sec(x) is sec(x)tan(x) right?

i also know that the first derivative of tan(x) is sec^2(x)

Where do i go from here? I really must appologize to you 11rdc11

I have not understood the concept of finding the anti-derivative at all

Would you please be so kind and explain? :( - Nov 9th 2008, 06:02 PM11rdc11
- Nov 9th 2008, 06:04 PMsess
- Nov 9th 2008, 06:26 PM11rdc11