The equation is as follows..
the derivative is (3x^2y-y^2)/(2xy-x^3)
So I set the denominator equal to zero, and solve..
2xy-x^2 = 0
Last edited by MadHotThunder; November 9th 2008 at 05:12 PM.
Reason: I ACTUALLY made progress.
Follow Math Help Forum on Facebook and Google+
View Tag Cloud