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Thread: Finding x-coordinates of a curve where the tangent line is vertical.

  1. November 9th 2008, 04:13 PM #1
    MadHotThunder
    MadHotThunder is offline
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    Finding x-coordinates of a curve where the tangent line is vertical.

    Oh, boy.
    Please help?

    The equation is as follows..
    xy^2-x^3y=6

    the derivative is (3x^2y-y^2)/(2xy-x^3)

    So I set the denominator equal to zero, and solve..
    2xy-x^2 = 0
    x(2y-x^2)=0
    x=0 y=x^2/2

    Now what!!?
    Last edited by MadHotThunder; November 9th 2008 at 05:12 PM. Reason: I ACTUALLY made progress.
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