Oh, boy. Please help? The equation is as follows.. xy^2-x^3y=6 the derivative is (3x^2y-y^2)/(2xy-x^3) So I set the denominator equal to zero, and solve.. 2xy-x^2 = 0 x(2y-x^2)=0 x=0 y=x^2/2 Now what!!?
Last edited by MadHotThunder; November 9th 2008 at 05:12 PM. Reason: I ACTUALLY made progress.
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