Oh, boy.

Please help?

The equation is as follows..

xy^2-x^3y=6

the derivative is (3x^2y-y^2)/(2xy-x^3)

So I set the denominator equal to zero, and solve..

2xy-x^2 = 0

x(2y-x^2)=0

x=0 y=x^2/2

Now what!!?

- Nov 9th 2008, 05:13 PMMadHotThunderFinding x-coordinates of a curve where the tangent line is vertical.
Oh, boy.

Please help?

The equation is as follows..

xy^2-x^3y=6

the derivative is (3x^2y-y^2)/(2xy-x^3)

So I set the denominator equal to zero, and solve..

2xy-x^2 = 0

x(2y-x^2)=0

x=0 y=x^2/2

Now what!!?