To determine the equation of the cylinder circumscribed to the beads: $\displaystyle (e1):(x-2)^2+(y-1)^2+z^2=25$ and $\displaystyle (e2):x^2+y^2+z^2=25$

Answer:

$\displaystyle x^2+4y^2+5z^2-4xy-125=0$

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- Nov 9th 2008, 02:29 PMApprentice123Cylinder and beads
To determine the equation of the cylinder circumscribed to the beads: $\displaystyle (e1):(x-2)^2+(y-1)^2+z^2=25$ and $\displaystyle (e2):x^2+y^2+z^2=25$

Answer:

$\displaystyle x^2+4y^2+5z^2-4xy-125=0$