How could i show that f(t)=exp(it), where i is square root of -1, is continuous?
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Originally Posted by johnbarkwith How could i show that f(t)=exp(it), where i is square root of -1, is continuous? Just pick an arbitrary value $\displaystyle c$ and show that $\displaystyle \forall{c}~\lim_{t\to{c^-}}e^{it}=\lim_{t\to{c^+}}e^{it}=e^{ic}$
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