1. If the area bounded by the parabola y = H - (H/R^2)x^2 and the x-axis is revolved about the y-axis, the resulting bullet-shaped solid is a segment of a paraboloid of revolution with height H and radius of base R. Show its volume is half the volume of the circumscribing cylinder
Okay so the thickness of the disk is dy and the area is (pi)x^2. How do I find the limits of integration and put x in terms of H and R? (assuming that is the right path to take) Thanks.