Results 1 to 2 of 2

Thread: Intergration

  1. Nov 9th 2008, 09:57 AM #1
    elitespart
    elitespart is offline
    Junior Member
    Joined
    Oct 2008
    Posts
    38

    Intergration - Help please.

    The area between y^2=x and x=4 is divided into two equal parts by the line x=a. Find a. So I got So I got a=cubed route of 16. right wrong? Thanks.
    Last edited by elitespart; Nov 9th 2008 at 11:47 AM.
    Follow Math Help Forum on Facebook and Google+
  2. Nov 9th 2008, 01:46 PM #2
    skeeter
    skeeter is offline
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    15,765
    Thanks
    3492
    a = \sqrt[3]{16} = 2\sqrt[3]{2}
    Follow Math Help Forum on Facebook and Google+
« Proving exp(2 pi i t) is a bijection onto unit circle | Help with a problem. »

Similar Math Help Forum Discussions

  1. Intergration
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Apr 23rd 2011, 06:14 PM
  2. Intergration help!!!!!!
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Oct 28th 2008, 06:41 AM
  3. help with intergration please
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Oct 14th 2008, 06:10 PM
  4. Intergration
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Aug 16th 2008, 10:33 PM
  5. Intergration
    Posted in the Calculus Forum
    Replies: 4
    Last Post: Jun 1st 2008, 06:17 PM

Search Tags


/mathhelpforum @mathhelpforum