Hello, just curious if anyone knows how I might find the Taylor/MacLaurin series of (1-x)^-3, x<1. I was thinking I could use a geometric series, but when I get into trying the expansion, it's messy.
Hello, just curious if anyone knows how I might find the Taylor/MacLaurin series of (1-x)^-3, x<1. I was thinking I could use a geometric series, but when I get into trying the expansion, it's messy.
Thanks.
Build the series from the definition of Taylor series see here. You
may as well construct the expansion about x=0.