Hello, just curious if anyone knows how I might find the Taylor/MacLaurin series of (1-x)^-3, x<1. I was thinking I could use a geometric series, but when I get into trying the expansion, it's messy.

Thanks.

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- Sep 26th 2006, 03:34 PMprimasapereTaylor/MacLaurin series expansion
Hello, just curious if anyone knows how I might find the Taylor/MacLaurin series of (1-x)^-3, x<1. I was thinking I could use a geometric series, but when I get into trying the expansion, it's messy.

Thanks. - Sep 26th 2006, 03:53 PMCaptainBlack
Build the series from the definition of Taylor series see here. You

may as well construct the expansion about x=0.

RonL