# Math Help - tangent line to the ellipse-zero in the denominator

1. ## tangent line to the ellipse-zero in the denominator

I need help with this one.

Find the tangent lines to the ellipse x^2 + 2y^2 +4x = 5 at the point (1,0)
I differentiated the equation implicitly to get this: (-2x-4)/4y
And im stuck here. cuz i get a ZERO in the denoinator.
$x^2 + 2y^2 + 4x = 5 \Rightarrow \frac{(x + 2)^2}{9} + \frac{2y^2}{9} = 1$.