it is a double integeration

integrate integrate dydx

where my x and y value is

1<x<0

2<y<4-2x

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- November 7th 2008, 11:36 PMslurmhow do i do this reverse integration
it is a double integeration

integrate integrate dydx

where my x and y value is

1<x<0

2<y<4-2x - November 7th 2008, 11:53 PMmr fantastic
- November 7th 2008, 11:57 PMslurm
yes i done it but it seems i cant attach a picture to show my graph

anyway after sketching

i found out my range changes as it is now dxdy

2<y<4

0<x<[(y-4)/-2] - November 7th 2008, 11:59 PMslurm
it seems that is is not correct because integration of dxdy should be equal to dydx

- November 8th 2008, 12:00 AMmr fantastic
- November 8th 2008, 12:02 AMslurm
oh no the range for x is 0 and 1, as if like 0 is lower boundary and 1 is upper boundary.. haha if only i could draw it in a text box it will be easier

- November 8th 2008, 12:16 AMmr fantastic
- November 8th 2008, 12:23 AMslurm
is this answer? but when i integrate the left side of ur ans i get 2 instead of 1

- November 8th 2008, 12:27 AMslurm
oh no , a mistake in my integration.... sorry,got it already .thx alot

- November 8th 2008, 12:32 AMslurm
yeah got it already, thanks alot another question i would like to ask since i be doing vector calculus

i have a weakness in sketching and finding the limits of the integral. like for example sketching a parabola and such , do u have any tips in sketching graphs - November 8th 2008, 12:33 AMmr fantastic
- November 8th 2008, 12:36 AMslurm
yeah .. alright , i must agree that pressure really makes diamond, although i know nothing about chemistry, alright thanks alot again