it is a double integeration

integrate integrate dydx

where my x and y value is

1<x<0

2<y<4-2x

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- Nov 7th 2008, 10:36 PMslurmhow do i do this reverse integration
it is a double integeration

integrate integrate dydx

where my x and y value is

1<x<0

2<y<4-2x - Nov 7th 2008, 10:53 PMmr fantastic
- Nov 7th 2008, 10:57 PMslurm
yes i done it but it seems i cant attach a picture to show my graph

anyway after sketching

i found out my range changes as it is now dxdy

2<y<4

0<x<[(y-4)/-2] - Nov 7th 2008, 10:59 PMslurm
it seems that is is not correct because integration of dxdy should be equal to dydx

- Nov 7th 2008, 11:00 PMmr fantastic
- Nov 7th 2008, 11:02 PMslurm
oh no the range for x is 0 and 1, as if like 0 is lower boundary and 1 is upper boundary.. haha if only i could draw it in a text box it will be easier

- Nov 7th 2008, 11:16 PMmr fantastic
- Nov 7th 2008, 11:23 PMslurm
is this answer? but when i integrate the left side of ur ans i get 2 instead of 1

- Nov 7th 2008, 11:27 PMslurm
oh no , a mistake in my integration.... sorry,got it already .thx alot

- Nov 7th 2008, 11:32 PMslurm
yeah got it already, thanks alot another question i would like to ask since i be doing vector calculus

i have a weakness in sketching and finding the limits of the integral. like for example sketching a parabola and such , do u have any tips in sketching graphs - Nov 7th 2008, 11:33 PMmr fantastic
- Nov 7th 2008, 11:36 PMslurm
yeah .. alright , i must agree that pressure really makes diamond, although i know nothing about chemistry, alright thanks alot again