Lets look at the first few terms of the Taylor series for f(x)=ln(1+x) centred
so df/dx(0) = 1
So the series starts:
Now look at your candidate answers. The first two can be ruled out as
the absolute value of the coefficient of x^2 is 2.
That leaves us with the second two. The fourth gives a -ve coefficient for
x, so it is ruled out, which leaves us with (c), which agrees with the terms
of the series that we know.