F(x) = x^4 - 18x^2 + 1; [-4,4}
F'(x) = 4x^3 -36x = 0
Critical points x = -3, x=3
x | f(x)= x^4 - 18x^2 + 1
-------------------------
-4 | -31
-3 | -80
3 | -80
4 | -31
I would had said the absolute max is -4 & 4 and min is -3, 3
The book says max = o, min = -3
Where did I go wrong?
f(x) = (1-x)/(x+3); [0,3]
I got .33333 for the max, -.3333 for the min. The book says max is 0 and min is 3. What did I miss?