Just wanted to know how to approach this problem i found Find f'(x) f(x)= x^x^x it looks like a staircase
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$\displaystyle y=x^{x^x}=e^{e^{x\ln{x}}\ln{x}}$ Use chain rule.
how would you apply the chain rule to this problem
$\displaystyle y = e^{e^{x\ln{x}}\ln{x}}$ $\displaystyle y' = e^{e^{x\ln{x}}\ln{x}} \left(\frac{e^{x\ln{x}}}{x}+\ln{x}\left(e^{x\ln{x} }\left(\ln{x}+1\right)\right)\right)$
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