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Math Help - Freaky problem

  1. #1
    Junior Member
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    Oct 2008
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    Freaky problem

    Just wanted to know how to approach this problem i found

    Find f'(x)
    f(x)= x^x^x
    it looks like a staircase
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  2. #2
    Super Member
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    y=x^{x^x}=e^{e^{x\ln{x}}\ln{x}}

    Use chain rule.
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  3. #3
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    how would you apply the chain rule to this problem
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  4. #4
    Super Member
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    y = e^{e^{x\ln{x}}\ln{x}}

    y' = e^{e^{x\ln{x}}\ln{x}} \left(\frac{e^{x\ln{x}}}{x}+\ln{x}\left(e^{x\ln{x}  }\left(\ln{x}+1\right)\right)\right)
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