Does this series converge?

**tttcomrader** · November 4th 2008, 04:53 PM

Does the series $\sum ^ \infty _{k=1} x^k$ on (0,1)? Pointwise or Uniformly?

Well, so far I have this:

Define the partial sum $S_n = \sum ^n _{k=1} x^k =1+x=x^2+...+x^n= \frac {1-x^{n+1}}{1-x}$

So the series converge point wise to $\frac {1}{1-x}$ ?

**Mathstud28** · November 4th 2008, 06:28 PM

Originally Posted by tttcomrader

Does the series $\sum ^ \infty _{k=1} x^k$ on (0,1)? Pointwise or Uniformly?

Well, so far I have this:

Define the partial sum $S_n = \sum ^n _{k=1} x^k =1+x=x^2+...+x^n= \frac {1-x^{n+1}}{1-x}$

So the series converge point wise to $\frac {1}{1-x}$ ?

Just consider $\lim_{x\to{0^-}}\sum_{n=0}^{\infty}x^n$ and use abel's theorem and then you can see that it does not converge unifomrly because it does not equal $\frac{1}{1-0}$

**Opalg** · November 5th 2008, 01:10 AM

Originally Posted by tttcomrader

Does the series $\sum ^ \infty _{k=1} x^k$ on (0,1)? Pointwise or Uniformly?

Well, so far I have this:

Define the partial sum $S_n = \sum ^n _{k=1} x^k =1+x+x^2+...+x^n= \frac {1-x^{n+1}}{1-x}$

So the series converge point wise to $\frac {1}{1-x}$ ?

The sum starts at k=1, not k=0, so you need to modify the formula for $S_n$ slightly.

To see whether or not the series converges uniformly, you need to think about what happens as $x\to1$ .

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