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Math Help - Does the series converge?

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    Does the series converge?

    Summation from n=1 ti infinity of (sin(1))^n.

    How can I break this up? I think it will be a geometric series...
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    \left| r \right| < 1 \Rightarrow \quad \sum\limits_{n = 1}^\infty  {r^n }  = \frac{r}{{1 - r}}
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    I thought it was r ^ (n-1)? And what is my r and my a?
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    Quote Originally Posted by veronicak5678 View Post
    Summation from n=1 ti infinity of (sin(1))^n.

    How can I break this up? I think it will be a geometric series...
    |\sin(1)|=|r|<1\Rightarrow\sum)_{n=1}^{\infty}\sin  ^n(1)=\frac{\sin(1)}{1-\sin(1)}
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  5. #5
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    Got it. Thank you!
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