$\displaystyle
\int ln(y)dy
$
wondering how i would integrate this
$\displaystyle u = \ln (x)$
$\displaystyle dv = dx$
according to the formula of itegrating by parts:
$\displaystyle \color{blue}\boxed{\int udv = uv - \int vdu}$
$\displaystyle = x\ln (x) - \int x(\frac {1}{x})dx$
$\displaystyle x\ln (x) - x + c$