1. ## Substitution and Integrate

The integral is 1/(1+cubert[x]) dx from 0 to 1. I'm supposed to make a substitution to express the integrand as a rational function and then evaluate the integral.

I got the part of x=u^2-1 and dx=2du but plugging into the equation and going from there I'm getting messed up somewhere.

2. Originally Posted by sfgiants13
The integral is 1/(1+cubert[x]) dx from 0 to 1. I'm supposed to make a substitution to express the integrand as a rational function and then evaluate the integral.

I got the part of x=u^2-1 and dx=2du but plugging into the equation and going from there I'm getting messed up somewhere.
$\int\frac{dx}{1+\sqrt[3]{x}}\overbrace{\mapsto}^{z^3=x}\int\frac{3z^2}{1+z }dz$