These are the last three problems that I need to know before the test .
Find f(x)'
A) f(x) = log (1-x)^2
B) f(x) = log9(2^x + 1)
C) f(x) = 2^(log(3)x)
The 9 is subscript in problem B
The 3 is subscript in problem C
Thanks alot for the help.
Edit: whoops, sorry Jameson, didn't see that you had posted again
I haven't seen this notation before, and I am assuming that f(x)' is the derivative of f(x). If this is not the case, please ignore me.These are the last three problems that I need to know before the test .
Find f(x)'
Remember the formula and/or use the chain rule.A) f(x) = log (1-x)^2
Use andB) f(x) = log9(2^x + 1)
Use all the formulas from the other 2 questions.C) f(x) = 2^(log(3)x)
no..? isnt the rule of logs : f(x)=log a (f(x)) , where a is a subscript. therefore f ' (x)= 1 1
___ . ___ . f ' (x)
ln a f(x)
sorry if you dont understand what i wrote..
so basically, for what you do is :
f ' (x) = 1 over (ln 10) times 1 over (1-x)^2 times 2(1-x)times(-1)
hope this helps..