Hello
$\displaystyle sin(2x^3 + y^2) = cos(x^2 + 2y^3)$
How would this be solved using implicit differentiation?
Thank you
I'll do the left hand side and let you do the right.
$\displaystyle \cos(2x^3+y^2) (6x^2+2y*y') = ... $
Use the chain rule. The outermost function in this case was the sine function, then multiply by the derivative of the inner terms. Same thing for the right hand side.
Then, you'll have to do some algebra to solve for y'.