I seem to be getting worse and worse at integrating haha.. I can get this in a form that looks simple but for the life of me cannot seem to get past it!!

$\displaystyle \int \frac{sin(kx)}{\sqrt{2+cos(kx)}}dx $ where k does not equal zero

let $\displaystyle cos(kx) = u $ therefore $\displaystyle dx = \frac{du}{-ksin(kx)} $

so it becomes $\displaystyle -\frac{1}{k} \int \frac{du}{\sqrt{2 + u}} $

for some reason I cannot get past here.. Very frustrating!!

Thanks in advance,