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Math Help - help with this calc problem - differentiation, continuity, has variables

  1. #1
    Junior Member LexiRae's Avatar
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    help with this calc problem - differentiation, continuity, has variables

    y=
    2x^2 + 3ax +1 if x is < or = 1
    mx+a if x>1
    what values for m and a make x continuous and differentiable at 1?

    i know the basic process: solve for x, set the limits equal, differentiate those 2 equations. but i get stuck with all the variables.
    thanks!!

    EDIT** yeah youre right i fixed it. but can anyone help me answer it?
    Last edited by LexiRae; November 2nd 2008 at 05:40 AM.
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  2. #2
    Member Nacho's Avatar
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    are you sure that is mx+a if x>0? I think that should say x>1
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  3. #3
    MHF Contributor
    skeeter's Avatar
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    y = 2x^2 + 3ax +1 if x \leq 1

    y = mx+a if x>1

    for continuity ...

    2(1)^2 + 3a(1) + 1 = m(1) + a

    for differentiability ...

    4(1) + 3a = m

    solve the system for a and m.
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  4. #4
    Member Nacho's Avatar
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    In general this problem solve whit skeeter method, only you know is that if the function is continue the lateral limit are equals
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