are you sure that is mx+a if x>0? I think that should say x>1
y=
2x^2 + 3ax +1 if x is < or = 1
mx+a if x>1
what values for m and a make x continuous and differentiable at 1?
i know the basic process: solve for x, set the limits equal, differentiate those 2 equations. but i get stuck with all the variables.
thanks!!
EDIT** yeah youre right i fixed it. but can anyone help me answer it?