$\displaystyle \int 62sin(11+16x) $ = $\displaystyle \frac {-62}{16}cos(11+16x) $ this correct?
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Originally Posted by jvignacio $\displaystyle \int 62sin(11+16x) $ = $\displaystyle \frac {-62}{16}cos(11+16x) $ this correct? Yes. Check it here: Wolfram Mathematica Online Integrator
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