R[0,1] is the vector space of all integrable functions on [0,1] does this define a norm? i think yes. because i cant find any axiom fails
Follow Math Help Forum on Facebook and Google+
Hi, How did you show that implies ?
isnt it obvious? u just show the upper riemann sum=lower riemann sum=0 ( by integrale) therefore, sup f=inf f=0
Originally Posted by szpengchao u just show the upper riemann sum=lower riemann sum=0 ( by integrale) therefore, sup f=inf f=0 This doesn't work for since one has but .
View Tag Cloud