The derivative, at x= 1, will give you the slope of the tangent.

calculate dy/dx and put x=1 in it to get the slope of tangent.

After that calculate the y - coordinate of the point, by putting x=1 in the eqn of curve, you will get (1, 6)

Now, find the eqn of tangent using point slope form of line,

y - 6 = 15 (x - 1)

y = 15x - 9