can any one answer this,,,,really annoying me??? Im told to find the centre foci and hyperbola of
I get everything except the asymptotes,, I think it involves limits or something because I dont get the conventional ax/b or was it bx/a because its switched around? Any way the foci was(1,3 and centre (1,3) thanks!
I presume you completed the square in to get or
In standard form, that is .
Now, here's a technique that is worth knowing: For very large values of x and y, the "1" on the right will be negligible compared with the large numbers we are subtracting on the left. The graph will be very close to (technically, "asymptotic to") .
That is equivalent to . Taking square roots of both sides we get the two equations
Those are the equations of the asymptotes to the hyperbola.