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Math Help - numerical analysis

  1. #1
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    numerical analysis

    How do I show that for any x0 < x1 < x2 < ... < xn, the fundamental Lagrange polynomials satisfy

    (the summation from j = 0 to n of lj(x)) = 1
    where lj(x) is the jth fundamental Lagrange polynomial of degree n ?

    I've been trying to work this out algebraically, but I don't really know where to start. Thanks for any help.
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  2. #2
    MHF Contributor arbolis's Avatar
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    I did the same problem about 6 months ago. If I remember well, you have to use the definition of Lagrange polynomial : check out Lagrange polynomial - Wikipedia, the free encyclopedia.
    I have no time to help you more (so sorry about that), but in
    (the summation from j = 0 to n of lj(x)) = 1
    where lj(x) is the jth fundamental Lagrange polynomial of degree n ?
    , don't you mean the product instead of the summation?
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