Evaluate the Integral ∫ 1/[(x^2) * sqrt(x^2 + 4)] dx
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no trigonometry needed, use the following substitution: $\displaystyle u = \frac{x} {{\sqrt {x^2 + 4} }}$
Originally Posted by thegush1 Evaluate the Integral ∫ 1/[(x^2) * sqrt(x^2 + 4)] dx you could try x =2tan(u) try the following page for more explanation integration by trigonometric substitution
$\displaystyle x = \frac{1}{u}$ works out nicely.
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