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Thread: finding the derivative

  1. #1
    Member
    Joined
    Oct 2008
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    109

    finding the derivative

    $\displaystyle
    xy = sin(x^2 + y^2)
    $

    $\displaystyle
    x \cdot y' + y = sin(x^2 + y^2)
    $

    when i take the derivative of the right side is it:

    $\displaystyle
    cos(x^2 + y^2) \cdot 2x \cdot 2yy'
    $
    or
    $\displaystyle
    cos(x^2 + y^2) \cdot 2x + cos(x^2 + y^2) \cdot 2yy'
    $

    or none of the above?
    thanks
    Last edited by qzno; Oct 30th 2008 at 03:16 PM.
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  2. #2
    Junior Member
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    Re: Derivative

    $\displaystyle
    cos(x^2 + y^2) \cdot 2x \cdot 2yy'
    $
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