Find the angle of theta with all real numbers (0,2,PIE) in radians, in quadrant 2 whose tangent is -4. Show results to two decimal places. theta= ___________________ radians
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Originally Posted by asweet1 Find the angle of theta with all real numbers (0,2,PIE) in radians, in quadrant 2 whose tangent is -4. Show results to two decimal places. theta= ___________________ radians Tanx=-4 use ur calculator and find the inverse tangent of -4 the answer u get is theta then u multiply the answer by pi_ 180
i got -1.32 as theta then mulyiplies by pi/180 and got -75.63 and it says im wrong
Originally Posted by asweet1 i got -1.32 as theta then mulyiplies by pi/180 and got -75.63 and it says im wrong change the mode to degrees
Originally Posted by asweet1 Find the angle of theta with all real numbers (0,2,PIE) in radians, in quadrant 2 whose tangent is -4. Show results to two decimal places. theta= ___________________ radians $\displaystyle \theta=arctan( -4)$ $\displaystyle \theta\approx-1.325817664$ radians. Reference angle in QII = $\displaystyle -1.325817664 + \pi=1.81577499$ radians.To the nearest 2 decimal places ==> 1.82 radians.
Originally Posted by masters $\displaystyle \theta=arctan( -4)$ $\displaystyle \theta\approx-1.325817664$ radians. Reference angle in QII = $\displaystyle -1.325817664 + \pi=1.81577499$ radians.To the nearest 2 decimal places ==> 1.82 radians. sry forgot it was in QII
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