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Thread: Exponentials and logarithims

  1. October 30th 2008, 12:30 PM #1
    gamboo
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    Exponentials and logarithims



    I get as far as dy/dx= -3e^-3x +2, then making this equal to zero, then going blank
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  2. October 30th 2008, 12:46 PM #2
    mr fantastic
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    Quote Originally Posted by gamboo View Post


    I get as far as dy/dx= -3e^-3x +2, then making this equal to zero, then going blank
    0 = -3e^{-3x} +2 \Rightarrow \frac{2}{3} = e^{-3x} \Rightarrow \ln \frac{2}{3} = -3x \Rightarrow x = -\frac{1}{3} \ln \frac{2}{3}.

    Substitute into y = e^{-3x} + 2x and simplify to get the given value of y.
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