Math Help - Integral (shouldn't be too hard)

1. Integral (shouldn't be too hard)

Hey guys, would be nice if I could have help with a quick integral.

$\int \frac{1}{x^2 - 5x + 4} dx$

I'm pretty sure that I need to make a substitution here, but I can't see how.

Cheers,

2. Originally Posted by U-God
Hey guys, would be nice if I could have help with a quick integral.

$\int \frac{1}{x^2 - 5x + 4} dx$

I'm pretty sure that I need to make a substitution here, but I can't see how.

Cheers,
Hey U-God,

I got this,

$\int \frac{1}{x^2 - 5x + 4} dx$

$\frac{1}{3} \int \frac{3}{x^2 - 5x + 4} dx$

$\frac{1}{3} \int \frac{3}{(x-1)(x-4)} dx$

$\frac{1}{3} \int \frac{-1}{(x-1)} + \frac{1}{(x-4)} dx$

$\frac{1}{3} (\ln{(x-4)} - \ln{(x-4)})$

I didn't see the need for any substitution... Its perfectly fine without any substitution