Hey guys, would be nice if I could have help with a quick integral.
$\displaystyle \int \frac{1}{x^2 - 5x + 4} dx $
I'm pretty sure that I need to make a substitution here, but I can't see how.
Cheers,
Hey U-God,
I got this,
$\displaystyle \int \frac{1}{x^2 - 5x + 4} dx $
$\displaystyle \frac{1}{3} \int \frac{3}{x^2 - 5x + 4} dx $
$\displaystyle \frac{1}{3} \int \frac{3}{(x-1)(x-4)} dx $
$\displaystyle \frac{1}{3} \int \frac{-1}{(x-1)} + \frac{1}{(x-4)} dx $
$\displaystyle \frac{1}{3} (\ln{(x-4)} - \ln{(x-4)})$
I didn't see the need for any substitution... Its perfectly fine without any substitution
Hopefully I've been helpful.
tsal15