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Math Help - Integral (shouldn't be too hard)

  1. #1
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    Integral (shouldn't be too hard)

    Hey guys, would be nice if I could have help with a quick integral.

     \int \frac{1}{x^2 - 5x + 4} dx

    I'm pretty sure that I need to make a substitution here, but I can't see how.

    Cheers,
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  2. #2
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    Talking

    Quote Originally Posted by U-God View Post
    Hey guys, would be nice if I could have help with a quick integral.

     \int \frac{1}{x^2 - 5x + 4} dx

    I'm pretty sure that I need to make a substitution here, but I can't see how.

    Cheers,
    Hey U-God,

    I got this,

     \int \frac{1}{x^2 - 5x + 4} dx

     \frac{1}{3} \int \frac{3}{x^2 - 5x + 4} dx

     \frac{1}{3} \int \frac{3}{(x-1)(x-4)} dx

     \frac{1}{3} \int \frac{-1}{(x-1)} + \frac{1}{(x-4)} dx

    \frac{1}{3} (\ln{(x-4)} - \ln{(x-4)})

    I didn't see the need for any substitution... Its perfectly fine without any substitution

    Hopefully I've been helpful.

    tsal15
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