evaluate the indefinite integral i come up with 8sqrt(u)+C and this answer is not working!
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Originally Posted by johnny4lsu evaluate the indefinite integral i come up with 8sqrt(u)+C and this answer is not working! I would take out a 1/4 since that's just a constant and rewrite as u^(-1/2). See if that makes it better.
that won't work either? Any other suggestions?
Originally Posted by johnny4lsu that won't work either? Any other suggestions? When you tried that, what did you get for your answer?
This is what i did! 4u^(-1/2)du (4u^(1/2))/(1/2) 8sqrt(u)+C
Originally Posted by johnny4lsu This is what i did! 4u^(-1/2)du (4u^(1/2))/(1/2) 8sqrt(u)+C You almost have it but the 4 should be a 1/4. That should make it better.
thank you very much. that was the problem! i appreciate the time.
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