# Math Help - How do I find the derivative

1. ## How do I find the derivative

Tan square root of (x^2 + 1)

2. Originally Posted by henri
Tan square root of (x^2 + 1)
$\frac{d}{dx}\bigg[\tan\left(\sqrt{x^2+1}\right)\bigg]=\sec^2\left(\sqrt{x^2+1}\right)\cdot\left(\sqrt{x ^2+1}\right)'=\frac{\sec^2\left(\sqrt{x^2+1}\right )x}{\sqrt{x^2+1}}$

3. note that Mathstud used the chain rule. be sure to look it up and familiarize yourself with it

4. thank you, I actually had the answer but was not sure