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Math Help - How do I find the derivative

  1. #1
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    How do I find the derivative

    Tan square root of (x^2 + 1)
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by henri View Post
    Tan square root of (x^2 + 1)
    \frac{d}{dx}\bigg[\tan\left(\sqrt{x^2+1}\right)\bigg]=\sec^2\left(\sqrt{x^2+1}\right)\cdot\left(\sqrt{x  ^2+1}\right)'=\frac{\sec^2\left(\sqrt{x^2+1}\right  )x}{\sqrt{x^2+1}}
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    note that Mathstud used the chain rule. be sure to look it up and familiarize yourself with it
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  4. #4
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    thank you, I actually had the answer but was not sure
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