Originally Posted by

**endiv** hello, sorry for using my first post on this help forum ^^; I've been trying to ask this question everywhere on the net and no one seems to be able to help. So I'm trying here. Anyway

**I'm trying to find the limit of x tan (8/x) as x approaches to infinity, using the l'hospital's rule.**

So far I've applied the rule, but I'm stuck at the last part. Here's my work so far.

Using the l'hospital's rule it turned out like this:

$\displaystyle sec^2 (8/x) * -8/x^2 / -8/x^2$

+the$\displaystyle -8/x^2$'s cancel out leaving me with

$\displaystyle

sec^2 (8/x)$

so now this is where I'm stuck...When you input infinity in (8/x) , I can't seem to find where the values are heading to... for some examples

$\displaystyle 8/80 = .1$

[tex]8/90 = 0.08888~

$\displaystyle 8/100$

so.. would these values be heading towards 0 ? For my final answer I ended up getting, sec^2 (0) = 1 ... I think I made a mistake around here somehwere, but I don't know what.

if you can help, it would be greatly appreciated!