The question is to evaluate the integral x/x-6 dx by partial fractions
This is how I've started
so giving
rearranging this to
and then I have
A+B = 1 due to the co-efficient of x^2 term of polynomial both sides
-12A-12B= -6 due to the co-efficient of x
and A+B = 0 due to the constant
I'm really having trouble on how to solve for these .