Results 1 to 2 of 2

Math Help - Area with Double Integral

  1. #1
    Junior Member
    Joined
    Sep 2008
    Posts
    26

    Area with Double Integral

    Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles x^2 + y^2 = 100 and x^2 - 10x +y^2 = 0
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Eater of Worlds
    galactus's Avatar
    Joined
    Jul 2006
    From
    Chaneysville, PA
    Posts
    3,001
    Thanks
    1
    If we convert the second circle to polar we have

    x^{2}+y^{2}-10x=0

    r^{2}-10rcos{\theta}=0

    r=10cos{\theta}

    The equation of the first circle is r=10

    The area between them is:

    \frac{1}{2}\int_{0}^{\frac{\pi}{2}}[10^{2}-(10cos{\theta})^{2}]d{\theta}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Double integral area problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 6th 2011, 08:02 AM
  2. surface area using double integral
    Posted in the Calculus Forum
    Replies: 3
    Last Post: August 2nd 2010, 02:58 AM
  3. Double integral area
    Posted in the Calculus Forum
    Replies: 3
    Last Post: November 30th 2009, 11:16 AM
  4. calculus 3, area/double integral
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 3rd 2009, 12:21 PM
  5. surface area ( double integral)
    Posted in the Calculus Forum
    Replies: 1
    Last Post: August 14th 2007, 03:50 PM

Search Tags


/mathhelpforum @mathhelpforum