Hi I'm trying to work out the second derivative of the following: 3x^2 / 2*sqrt(x^3+x^3) Can anyone help? Not sure if I need to derive whats in the sqrt also as its the second derivative?
Follow Math Help Forum on Facebook and Google+
3x^2 / 2*sqrt(x^3+x^3) I'm assuming the given expression is ... $\displaystyle \frac{3x^2}{2\sqrt{x^3 + x^3}} = \frac{3x^2}{2\sqrt{2x^3}} = \frac{3}{2\sqrt{2}} \cdot \sqrt{x}$ correct?
View Tag Cloud