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Math Help - Analysis problem

  1. #1
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    Analysis problem

    Let g: [a,b] --> [c,d] be a continuous function in x_0\in [a,b], and f: [c,d] --> R a continuous function in g( x_0) \in [c,d]

    Show that f o g: [a,b] --> R defined by (f o g)(x) = f(g(x)) \forallx \in [a,b] is continuous in x_0 \in [a,b]
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  2. #2
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    Anyone have any ideas on solving this?
    Last edited by Cato; October 30th 2008 at 08:46 AM.
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  3. #3
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    Hello,
    Quote Originally Posted by Cato View Post
    Let g: [a,b] --> [c,d] be a continuous function in x_0\in [a,b], and f: [c,d] --> R a continuous function in g( x_0) \in [c,d]

    Show that f o g: [a,b] --> R defined by (f o g)(x) = f(g(x)) \forallx \in [a,b] is continuous in x_0 \in [a,b]
    Use the definition of continuity for f in x_0 :
    \forall \epsilon > 0,~ \exists \delta > 0,~ |x-x_0|< \delta \Rightarrow |f(x)-f(x_0)|< \epsilon
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  4. #4
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    Quote Originally Posted by Cato View Post
    Show that f o g: [a,b] --> R defined by (f o g)(x) = f(g(x)) \forallx \in [a,b] is continuous in x_0 \in [a,b]
    Let me rephrase the problem a little. Let g: D_1 \to D_2 and f: D_2 \to \mathbb{R}. Let g be continous at x_0 \in D_1 and f be continous at g(x_0) \in D_2. Let \epsilon > 0. There is \delta > 0 so that if y\in D_2 \text{ and }|y-g(x_0)| < \delta \implies |f(y) - f(g(x_0))| < \epsilon. There is \delta_1 > 0 so that x\in D_1 \text{ and }|x-x_0| < \delta_1 \implies |g(x) - g(x_0)| < \delta \implies |f(g(x)) - f(g(x_0))| < \epsilon. Thus, we see that f\circ g is continous at x_0.
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