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Math Help - Limit as x->[infinity]

  1. #1
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    Limit as x->[infinity]

    lim(n->[infinity]) (1+(1/n))^n = ????
    Last edited by InfinitePartsInHarmony; October 29th 2008 at 08:57 AM.
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  2. #2
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    Wink ..

    Hello
    Q.lim(n->[infinity]) (1+(1/n))^n = ????
    I suppose u know

    Lt x->0[log (1+x) / x]=1

    so lhs=
    lim(n->[infinity]) (1+(1/n))^n=e^ Lt (n->infinity)[nlog (1+1/n)]

    take 1/n=x and Zoom ahead
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