lim(n->[infinity]) (1+(1/n))^n = ????
Last edited by InfinitePartsInHarmony; October 29th 2008 at 09:57 AM.
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Hello Q.lim(n->[infinity]) (1+(1/n))^n = ???? I suppose u know Lt x->0[log (1+x) / x]=1 so lhs= lim(n->[infinity]) (1+(1/n))^n=e^ Lt (n->infinity)[nlog (1+1/n)] take 1/n=x and Zoom ahead
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