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Math Help - DERIVATE OF A INVERSE FUNCTION...

  1. #1
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    DERIVATE OF A INVERSE FUNCTION...

    Y= 1/ (x^2 +1) i used the chain rule.

    y=(x^2 +1)^ -1 y= (-v^-2)(2x)(1) where v: x^2 +1

    y=
    ________1________
    ( -2x (x^2 +1)^2 )

    thats incorrect could someone tell me where is my mistake?
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  2. #2
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    y = (x^2+1)^{-1}

    y' = -(x^2+1)^{-2} \cdot 2x

    y' = -\frac{2x}{(x^2+1)^2}
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  3. #3
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    Quote Originally Posted by skeeter View Post
    y = (x^2+1)^{-1}

    y' = -(x^2+1)^{-2} \cdot 2x

    y' = -\frac{2x}{(x^2+1)^2}


    thanks i see it...
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