Use the intermediate value theorem to show that f(x) = -x^4 + 3x^3 - 2x + 1 has zero between 2 and 3
I did
a=2, b=3
so
f(a) = -(2)^4 + 3(2)^3 - 2(2) + 1
= -16 + 24 - 4 + 1
= -20 + 25
= 5
f(b) = -(3)^4 + 3(3)^3 - 2(3) + 1
= - 81 + 81 - 6 + 1
= -87 + 82
= -5
Is this correct?


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