1. ## integration check #2

$\displaystyle \int \frac {1}{\sqrt[3]{4-5x}}$

$\displaystyle \int(4-5x)^{-1/3}$

$\displaystyle = \frac {-3}{10}(4-5x)^{2/3}$

is this correct? thanks you

2. Yes. Don't forget to add a plus C.

3. Originally Posted by jvignacio
$\displaystyle \int \frac {1}{\sqrt[3]{4-5x}}$

$\displaystyle \int(4-5x)^{-1/3}$

$\displaystyle = \frac {-3}{10}(4-5x)^{2/3}$

is this correct? thanks you
yes

you forgot the +C again

for the record, you can always check your answer by differentiating what you got. if you take the derivative of the answer, you should get the original integrand

4. Originally Posted by Chop Suey
Yes. Don't forget to add a plus C.
every integration u add + C ?

5. Originally Posted by jvignacio
every integration u add + C ?
only the indefinite ones. that is, the ones without integration limits (those numbers attached to the top and bottom of the integration sign)

6. You might want to check you answer in the following websites listed in this thread. Hope it helps.

http://www.mathhelpforum.com/math-he...tegration.html

7. Originally Posted by tester85
You might want to check you answer in the following websites listed in this thread. Hope it helps.

http://www.mathhelpforum.com/math-he...tegration.html

thanks for that.. ill be sure to have a look at em next time